(x-3)(x^2+4x+5)=0

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Solution for (x-3)(x^2+4x+5)=0 equation:


Simplifying
(x + -3)(x2 + 4x + 5) = 0

Reorder the terms:
(-3 + x)(x2 + 4x + 5) = 0

Reorder the terms:
(-3 + x)(5 + 4x + x2) = 0

Multiply (-3 + x) * (5 + 4x + x2)
(-3(5 + 4x + x2) + x(5 + 4x + x2)) = 0
((5 * -3 + 4x * -3 + x2 * -3) + x(5 + 4x + x2)) = 0
((-15 + -12x + -3x2) + x(5 + 4x + x2)) = 0
(-15 + -12x + -3x2 + (5 * x + 4x * x + x2 * x)) = 0
(-15 + -12x + -3x2 + (5x + 4x2 + x3)) = 0

Reorder the terms:
(-15 + -12x + 5x + -3x2 + 4x2 + x3) = 0

Combine like terms: -12x + 5x = -7x
(-15 + -7x + -3x2 + 4x2 + x3) = 0

Combine like terms: -3x2 + 4x2 = 1x2
(-15 + -7x + 1x2 + x3) = 0

Solving
-15 + -7x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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